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Grade 9 Notes of Linear Equations|| Compulsory Mathematics

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Simultaneous equations are a powerful tool to uncover unknown values that satisfy multiple conditions at once. By applying substitution, elimination, or graphical methods step by step, we can solve any problem with precision and clarity. Mastering these techniques makes solving real-life algebra problems much easier and more intuitive.

Simultaneous Linear Equations 

When two or more equations have the same variables, solving them together is called simultaneous equations.

Example: A customer pays Rs. 1050 for 3 kg oyster mushrooms and 2 kg white button mushrooms, while another pays Rs. 1200 for 2 kg oyster and 3 kg white button mushrooms.

Let cost of 1 kg oyster mushroom = x and 1 kg white button = y

Equations:
3x + 2y = 1050 …(i)
2x + 3y = 1200 …(ii)

Solving these equations gives the cost of each mushroom type.

Methods of Solving Simultaneous Equations

Substitution Method

Elimination Method

Graphical Method

Substitution Method

Example 1: Solve 3x + 2y = 1050 and 2x + 3y = 1200

Solution:
From equation (i):
3x + 2y = 1050
3x = 1050 - 2y
x = (1050 - 2y)/3

Substitute x in equation (ii):
2x + 3y = 1200
2*((1050 - 2y)/3) + 3y = 1200
(2100 - 4y)/3 + 3y = 1200
Multiply both sides by 3:
2100 - 4y + 9y = 3600
5y = 1500
y = 300

Substitute y in equation (i):
3x + 2*300 = 1050
3x + 600 = 1050
3x = 450
x = 150

Solution: Oyster mushroom = Rs.150/kg, White button mushroom = Rs.300/kg

Elimination Method

Example 2: Solve 4x + 3y = 100 and 5x + 2y = 90

Solution:
Multiply equation (i) by 2:
8x + 6y = 200
Multiply equation (ii) by 3:
15x + 6y = 270
Subtract the first from the second:
15x + 6y - (8x + 6y) = 270 - 200
7x = 70
x = 10

Substitute x in equation (i):
4*10 + 3y = 100
40 + 3y = 100
3y = 60
y = 20

Solution: Small copy = Rs.10, Large copy = Rs.20

Graphical Method

Express equations in slope-intercept form: y = mx + c

Plot points and draw lines

Intersection point = solution

Example 3: Solve 2x + 3y = 12 and x + 2y = 7

Solution:
y = (12 - 2x)/3
y = (7 - x)/2

Create table of values:
Equation 1: x=0 ⇒ y=4, x=3 ⇒ y=2, x=6 ⇒ y=0
Equation 2: x=1 ⇒ y=3, x=3 ⇒ y=2, x=5 ⇒ y=1

Intersection point = (3, 2)
Solution: x = 3, y = 2

Important Questions with Solutions

1. Solve x + y = 7 and x - y = 2
or, x = y + 2
or, (y + 2) + y = 7
or, 2y + 2 = 7
or, 2y = 5
or, y = 2.5
or, x = y + 2 = 4.5

2. Solve 3x - 2y = 11 and 3x + y = 15
or, From second equation: y = 15 - 3x
or, Substitute in first: 3x - 2(15 - 3x) = 11
or, 3x - 30 + 6x = 11
or, 9x = 41
or, x = 41/9
or, y = 15 - 3*(41/9) = 104/9

3. Solve 4x + 3y = 100 and 5x + 2y = 90
or, Use elimination method
or, x = 10, y = 20

4. Solve 3x + 2y = 11 and 4x - 3y = 9
or, Use elimination method
or, x = 3, y = 1

5. Solve 2x + 3y = 12 and x + 2y = 7
or, From second equation: x = 7 - 2y
or, Substitute in first: 2(7 - 2y) + 3y = 12
or, 14 - 4y + 3y = 12
or, -y + 14 = 12
or, y = 2
or, x = 7 - 2*2 = 3

6. Cost of chicken and mutton problem
or, 2x + y = 1500
or, x + 2y = 1950
or, Solve equations: x = 700, y = 1000

7. Rectangular playground: perimeter = 32, breadth = 1/3 length
or, 2(l + b) = 32 → l + b = 16
or, b = l/3 → l + l/3 = 16
or, 4l/3 = 16
or, l = 12
or, b = 4

8. Solve x + y = 16 and x - y = -4
or, x = y - 4
or, (y - 4) + y = 16
or, 2y - 4 = 16
or, 2y = 20
or, y = 10
or, x = y - 4 = 6

9. Solve 3x + y = 15 and 2x + 3y = 17
or, Multiply first by 3: 9x + 3y = 45
or, Subtract second equation: (9x + 3y) - (2x + 3y) = 45 - 17
or, 7x = 28
or, x = 4
or, Substitute x in first: 3*4 + y = 15 → y = 3

10. Solve 5x - y = 23 and 3x - 2y = 4
or, Multiply first by 2: 10x - 2y = 46
or, Subtract second: (10x - 2y) - (3x - 2y) = 46 - 4
or, 7x = 42
or, x = 6
or, Substitute x in second: 3*6 - 2y = 4 → 18 - 2y = 4
or, 2y = 14 → y = 7

11. Solve x + y = 25 and x - y = 5
or, x = y + 5
or, (y + 5) + y = 25 → 2y + 5 = 25
or, 2y = 20 → y = 10
or, x = y + 5 = 15

12. Solve x + 2y = 6 and 2x + y = 6
or, Multiply second by 2: 4x + 2y = 12
or, Subtract first: (4x + 2y) - (x + 2y) = 12 - 6
or, 3x = 6 → x = 2
or, Substitute x: 2 + 2y = 6 → 2y = 4 → y = 2

13. Solve 2x + y = 5 and x - y = 1
or, x = y + 1
or, 2(y + 1) + y = 5
or, 2y + 2 + y = 5 → 3y + 2 = 5
or, 3y = 3 → y = 1
or, x = y + 1 = 2

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